Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The number of distinct solutions of the equation
cos 2 2x + cos 4 x + sin 4 x + cos 6 x + sin 6 x = 2 in the interval [0, 2 π ] is
Text Solution
Verified by ExpertsThe correct answer is:
8
(8)
Sol.
cos 2 2x + cos 4 x + sin 4 x + cos 6 x + sin 6 x = 2
⇒
cos 2 2x + 1 –
sin 2 2x + 1 –
sin 2 2x = 2
⇒ cos 2 2x = sin 2 2x
⇒ tan 2 2x = 1
Now 2x ∈ [0, 4 π ] ⇒ x = 
so number of solution = 8
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Indicate all correct alternatives, where base of the log is 2.
The equation x (3/4) (logx)² + logx …
The number log 2 7 is :
Find all real numbers x which satisfy the equation
2 log 2 log 2 x + log 1/2 log 2 = 1.
Solve the equation log 3/4 log 8 (x 2 + 7) + log 1/2 log 1/4 (x 2 + 7) − 1 = − 2.
The number of solution(s) of log 4 (x – 1) = log 2 (x – 3) is/are
Let f(x) =
Column – Ι Column – ΙΙ